[01/11] argv-array: use size_t for count and alloc
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Message ID 20200728202152.GA1021513@coredump.intra.peff.net
State New
Headers show
Series
  • renaming argv_array
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Commit Message

Jeff King July 28, 2020, 8:21 p.m. UTC
On most 64-bit platforms, "int" is significantly smaller than a size_t,
which could lead to integer overflow and under-allocation of the array.
It's probably impossible to trigger in practice, as it would imply on
the order of 2^32 individual allocations. Even if was possible to grow
an array in that way (and we typically only use it for sets of strings,
like command line options), each allocation needs a pointer, malloc
overhead, etc. You'd quite likely run out of RAM before succeeding in
such an overflow.

But all that hand-waving aside, it's easy enough to use the correct
type, so let's do so.

Signed-off-by: Jeff King <peff@peff.net>
---
This one is obviously of value even without the renaming.

 argv-array.h | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

Patch
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diff --git a/argv-array.h b/argv-array.h
index a7d3b10707..4fc57b6902 100644
--- a/argv-array.h
+++ b/argv-array.h
@@ -29,8 +29,8 @@  extern const char *empty_argv[];
  */
 struct argv_array {
 	const char **argv;
-	int argc;
-	int alloc;
+	size_t argc;
+	size_t alloc;
 };
 
 #define ARGV_ARRAY_INIT { empty_argv, 0, 0 }