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[2/2] btrfs: remove redundant release of alloc_state

Message ID b824ce907b5081a1eebea8c206f325d20d36e655.1680619177.git.anand.jain@oracle.com (mailing list archive)
State New, archived
Headers show
Series minor cleanups for device close and free functions | expand

Commit Message

Anand Jain April 4, 2023, 2:55 p.m. UTC 
Commit 321f69f86a0f ("btrfs: reset device back to allocation state when
removing") included adding extent_io_tree_release(&device->alloc_state)
to btrfs_close_one_device(), which had already been called in
btrfs_free_device().

The alloc_state tree (IO_TREE_DEVICE_ALLOC_STATE), is created in
btrfs_alloc_device() and released in btrfs_close_one_device(). Therefore,
the additional call to extent_io_tree_release(&device->alloc_state) in
btrfs_free_device() is unnecessary and can be removed.

Signed-off-by: Anand Jain <anand.jain@oracle.com>
---
 fs/btrfs/volumes.c | 1 -
 1 file changed, 1 deletion(-)
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Patch

diff --git a/fs/btrfs/volumes.c b/fs/btrfs/volumes.c
index 0e3677650a78..c201d72f798e 100644
--- a/fs/btrfs/volumes.c
+++ b/fs/btrfs/volumes.c
@@ -395,7 +395,6 @@  void btrfs_free_device(struct btrfs_device *device)
 {
 	WARN_ON(!list_empty(&device->post_commit_list));
 	rcu_string_free(device->name);
-	extent_io_tree_release(&device->alloc_state);
 	btrfs_destroy_dev_zone_info(device);
 	kfree(device);
 }