@@ -101,7 +101,12 @@ struct bpf_htab {
struct bpf_lru lru;
};
struct htab_elem *__percpu *extra_elems;
- atomic_t count; /* number of elements in this hashtable */
+ /* number of elements in non-preallocated hashtable are kept
+ * in either pcount or count
+ */
+ struct percpu_counter pcount;
+ atomic_t count;
+ bool use_percpu_counter;
u32 n_buckets; /* number of hash buckets */
u32 elem_size; /* size of each element in bytes */
u32 hashrnd;
@@ -552,6 +557,29 @@ static struct bpf_map *htab_map_alloc(union bpf_attr *attr)
htab_init_buckets(htab);
+/* compute_batch_value() computes batch value as num_online_cpus() * 2
+ * and __percpu_counter_compare() needs
+ * htab->max_entries - cur_number_of_elems to be more than batch * num_online_cpus()
+ * for percpu_counter to be faster than atomic_t. In practice the average bpf
+ * hash map size is 10k, which means that a system with 64 cpus will fill
+ * hashmap to 20% of 10k before percpu_counter becomes ineffective. Therefore
+ * define our own batch count as 32 then 10k hash map can be filled up to 80%:
+ * 10k - 8k > 32 _batch_ * 64 _cpus_
+ * and __percpu_counter_compare() will still be fast. At that point hash map
+ * collisions will dominate its performance anyway. Assume that hash map filled
+ * to 50+% isn't going to be O(1) and use the following formula to choose
+ * between percpu_counter and atomic_t.
+ */
+#define PERCPU_COUNTER_BATCH 32
+ if (attr->max_entries / 2 > num_online_cpus() * PERCPU_COUNTER_BATCH)
+ htab->use_percpu_counter = true;
+
+ if (htab->use_percpu_counter) {
+ err = percpu_counter_init(&htab->pcount, 0, GFP_KERNEL);
+ if (err)
+ goto free_map_locked;
+ }
+
if (prealloc) {
err = prealloc_init(htab);
if (err)
@@ -878,6 +906,31 @@ static void htab_put_fd_value(struct bpf_htab *htab, struct htab_elem *l)
}
}
+static bool is_map_full(struct bpf_htab *htab)
+{
+ if (htab->use_percpu_counter)
+ return __percpu_counter_compare(&htab->pcount, htab->map.max_entries,
+ PERCPU_COUNTER_BATCH) >= 0;
+ return atomic_read(&htab->count) >= htab->map.max_entries;
+}
+
+static void inc_elem_count(struct bpf_htab *htab)
+{
+ if (htab->use_percpu_counter)
+ percpu_counter_add_batch(&htab->pcount, 1, PERCPU_COUNTER_BATCH);
+ else
+ atomic_inc(&htab->count);
+}
+
+static void dec_elem_count(struct bpf_htab *htab)
+{
+ if (htab->use_percpu_counter)
+ percpu_counter_add_batch(&htab->pcount, -1, PERCPU_COUNTER_BATCH);
+ else
+ atomic_dec(&htab->count);
+}
+
+
static void free_htab_elem(struct bpf_htab *htab, struct htab_elem *l)
{
htab_put_fd_value(htab, l);
@@ -886,7 +939,7 @@ static void free_htab_elem(struct bpf_htab *htab, struct htab_elem *l)
check_and_free_fields(htab, l);
__pcpu_freelist_push(&htab->freelist, &l->fnode);
} else {
- atomic_dec(&htab->count);
+ dec_elem_count(htab);
l->htab = htab;
call_rcu(&l->rcu, htab_elem_free_rcu);
}
@@ -970,16 +1023,15 @@ static struct htab_elem *alloc_htab_elem(struct bpf_htab *htab, void *key,
l_new = container_of(l, struct htab_elem, fnode);
}
} else {
- if (atomic_inc_return(&htab->count) > htab->map.max_entries)
- if (!old_elem) {
+ if (is_map_full(htab))
+ if (!old_elem)
/* when map is full and update() is replacing
* old element, it's ok to allocate, since
* old element will be freed immediately.
* Otherwise return an error
*/
- l_new = ERR_PTR(-E2BIG);
- goto dec_count;
- }
+ return ERR_PTR(-E2BIG);
+ inc_elem_count(htab);
l_new = bpf_mem_cache_alloc(&htab->ma);
if (!l_new) {
l_new = ERR_PTR(-ENOMEM);
@@ -1021,7 +1073,7 @@ static struct htab_elem *alloc_htab_elem(struct bpf_htab *htab, void *key,
l_new->hash = hash;
return l_new;
dec_count:
- atomic_dec(&htab->count);
+ dec_elem_count(htab);
return l_new;
}
@@ -1495,6 +1547,8 @@ static void htab_map_free(struct bpf_map *map)
free_percpu(htab->extra_elems);
bpf_map_area_free(htab->buckets);
bpf_mem_alloc_destroy(&htab->ma);
+ if (htab->use_percpu_counter)
+ percpu_counter_destroy(&htab->pcount);
for (i = 0; i < HASHTAB_MAP_LOCK_COUNT; i++)
free_percpu(htab->map_locked[i]);
lockdep_unregister_key(&htab->lockdep_key);