[0/1] Handle /proc/self/exe in execve

Message

[e-mail] Aug. 7, 2019, 1:54 p.m. UTC

From: Olivier Dion <[e-mail]>

When the emulated process try to execve itself through /proc/self/exe,
QEMU user will be executed instead of the process.

The following short program demonstrated that:
----------------------------------------------------------------------
#include <stdio.h>
#include <string.h>
#include <unistd.h>


static char *ARGV0 = "STOP";
static char *ARGV1 = "-this-is-not-an-option";


int main(int argc, char *argv[], char *environ[])
{
        (void)argc;
        if (strcmp(argv[0], ARGV0) == 0)
                return 0;
        argv[0] = ARGV0;
        argv[1] = ARGV1;
        execve("/proc/self/exe", (char **const)argv,
               (char **const)environ);
        perror("execve");
        return 1;
}
----------------------------------------------------------------------

Will output:
----------------------------------------------------------------------
qemu: unknown option 'this-is-not-an-option'
----------------------------------------------------------------------

Olivier Dion (1):
  linux-user:  Handle /proc/self/exe in syscall execve

 linux-user/syscall.c | 13 ++++++++++++-
 1 file changed, 12 insertions(+), 1 deletion(-)