[18/20] zsmalloc: Convert to migrate_folio

Commit Message

Matthew Wilcox June 6, 2022, 8:40 p.m. UTC

zsmalloc doesn't really use folios, but it needs to be called like this
in order to migrate an individual page.  Convert from a folio back to
a page until we decide how to handle migration better for zsmalloc.

Signed-off-by: Matthew Wilcox (Oracle) <[e-mail]>
---
 mm/zsmalloc.c | 8 +++++---
 1 file changed, 5 insertions(+), 3 deletions(-)

Patch

diff --git a/mm/zsmalloc.c b/mm/zsmalloc.c
index 5d5fc04385b8..8ed79121195a 100644
--- a/mm/zsmalloc.c
+++ b/mm/zsmalloc.c
@@ -1865,9 +1865,11 @@  static bool zs_page_isolate(struct page *page, isolate_mode_t mode)
 	return true;
 }
 
-static int zs_page_migrate(struct address_space *mapping, struct page *newpage,
-		struct page *page, enum migrate_mode mode)
+static int zs_migrate_folio(struct address_space *mapping,
+		struct folio *dst, struct folio *src, enum migrate_mode mode)
 {
+	struct page *newpage = &dst->page;
+	struct page *page = &src->page;
 	struct zs_pool *pool;
 	struct size_class *class;
 	struct zspage *zspage;
@@ -1966,7 +1968,7 @@  static void zs_page_putback(struct page *page)
 
 static const struct address_space_operations zsmalloc_aops = {
 	.isolate_page = zs_page_isolate,
-	.migratepage = zs_page_migrate,
+	.migrate_folio = zs_migrate_folio,
 	.putback_page = zs_page_putback,
 };